Dear student,
Given A.P is 10.0,10.5,11.0,11.5,.....
first term of this A.P is a1 =10.0
second term of this A.P is a2 =10.5
common difference of an A.P is given by (i.e.,d=an+1 −an )
putting n=1 in above equation,
d=a2 −a1 =10.5−10=0.5
hence common difference for this A.P is d=0.5
the nth term of an A.P is given by.
an =a1 +(n−1)d
⟹an =10+(n−1)(0.5)
⟹an =10+0.5n−0.5
⟹an =9.5+0.5n...eq(1)
for finding 11th term (a 11 )of this A.P
put n=11 in above eq(1)
⟹a11 =9.5+0.5×11
⟹a11 =9.5+5.5
⟹a11 =15.0
Regards.