Find:-
23.1÷100
When we divide a number by 100, the answer is obtained by shifting the decimal in the number to the left by two digits
Given 23.1÷100
=23110÷100=23110×1100=2311000=0.231
Hence, the required solution is 0.231
The daily maximum temperature (in degree Celsius) recorded in a certain city during the month of November are as follows:
24.5,25.8,25.6,20.7,21.8,20.5,20.6,20.9,22.3,22.7,23.1,22.8,22.9,21.7,21.3,20.5.,20.9,23.1,22.4,21.5,22.7,22.8,22.0,23.9,24.7,22.8,23.8,24.6,21.1,23.9.
Represent them as a frequency distribution table with class size 1°C.