Find 3 irrational numbers between 4 & 5. [2 MARKS]

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Solution

Concept : 1 mark
Calculation : 1 Mark

$4 \times 5 = 20$ isn't a square

Hence 1 number is $\sqrt{20} = 2 \sqrt{5}$

Similarly $8 \sqrt{5}$ isn't a square

so $\sqrt{8 \sqrt{5}}$ = $\sqrt{320}$ is the second number

so $4^{2} = 16$ and $5^{2} = 25$

Hence $\sqrt{19}$ is the third

Any method can be used,use your calculator to verify

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Find 3 irrational numbers between 4 & 5. [2 MARKS]

Concept : 1 mark Calculation : 1 Mark 4×5=20 isn't a square Hence 1 number is √20=2√5 Similarly 8√5 isn't a square so √8√5=√320 is the second number so 42=16 and 52=25 Hence √19 is the third Any method can be used,use your calculator to verify