Find $(3^{o} + 4^{- 1}) \times 2^{2}$

Open in App

Solution

$(3^{0} + 4^{- 1}) \times 2^{2} = (1 + 0.25) \times 4 = \frac{5}{4} \times 4 = 5$

Suggest Corrections

Similar questions

H_{3} P O_{4} + H_{2} O \to H_{3} O^{+} + H - 2 P O_{4}^{-}; p K_{1} = 2.15 H_{2} P O_{4}^{-} + H_{2} O \to H_{3} O^{+} H P O_{4}^{2 -}; p K_{2} = 7.20

Hence pH of 0.01 M

N a H_{2} P O_{4}

is:

Q. compute:-

{(- 3)}^{4} - {(\sqrt[4]{3})}^{o} \times {(- 2)}^{5} \div {(64)}^{\frac{2}{3}}

Q. Find the value of

\frac{x^{o} - 3^{o}}{2^{o}}

$F e C r_{2} O_{4} + N a_{2} C O_{3} + O_{2} ⟶ X + Y + C O_{2}$
Mention X and Y.

$1 + \frac{1^{2} + 2^{2}}{2!} + \frac{1^{2} + 2^{2} + 3^{2}}{3!} + \frac{1^{2} + 2^{2} + 3^{2} + 4^{2}}{4!} + . . . \infty = \frac{b}{6} e$ . Find $b$

Join BYJU'S Learning Program

Find (3o+4−1)×22

(30+4−1)×22=(1+0.25)×4=54×4=5

Find $(3^{o} + 4^{- 1}) \times 2^{2}$

$(3^{0} + 4^{- 1}) \times 2^{2} = (1 + 0.25) \times 4 = \frac{5}{4} \times 4 = 5$