Find $(3 x^{2} - 7) (3 x^{2} - 8)$ when $x = 1$

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Solution

Given, $(3 x^{2} - 7) (3 x^{2} - 8)$ for $x = 1$

$= (3 (1)^{2} - 7) (3 (1)^{2} - 8)$
$= (3 - 7) (3 - 8)$

$= (- 4) (- 5) = 20$

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