Find $4 a b c - 6 c a + 4 a b - 2 b c$ , if $a = 2, b = - 3$ and $c = 5$ .

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Solution

Given the algebraic expression, $4 a b c - 6 c a + 4 a b - 2 b c$
For values $a = 2, b = - 3$ and $c = 5$ , putting all the values, we get:
$4 a b c - 6 c a + 4 a b - 2 b c = 4 \times 2 \times (- 3) \times 5 - 6 \times 5 \times 2 + 4 \times 2 \times (- 3) - 2 \times (- 3) \times 5 = - 120 - 60 - 24 + 30 = - 204 + 30 = - 174$
Hence, the value of $4 a b c - 6 c a + 4 a b - 2 b c$ for $a = 2, b = - 3$ and $c = 5$ is equal to $- 174$ .

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