Question

Find $\frac{5}{8}$ of $9\frac{2}{3}$

Answer 1

Find the required value:

The required value can be calculated as,

$\frac{5}{8}\mathrm{of}9\frac{2}{3}=\frac{5}{8}\times 9\frac{2}{3}$ $\left[\because aofb=a\times b\right]$

$\Rightarrow \frac{5}{8}\mathrm{of}9\frac{2}{3}=\frac{5}{8}\times \frac{\left(9\times 3\right)+2}{3}$ $\left[\because a\frac{b}{c}=\frac{\left(a\times c\right)+b}{c}\right]$

$\Rightarrow \frac{5}{8}\mathrm{of}9\frac{2}{3}=\frac{5}{8}\times \frac{27+2}{3}$

$\Rightarrow \frac{5}{8}\mathrm{of}9\frac{2}{3}=\frac{5}{8}\times \frac{29}{3}$

$\Rightarrow \frac{5}{8}\mathrm{of}9\frac{2}{3}=\frac{5\times 29}{8\times 3}$ $\left[\because \frac{a}{b}\times \frac{c}{d}=\frac{a\times c}{b\times d}\right]$

$\Rightarrow \frac{5}{8}\mathrm{of}9\frac{2}{3}=\frac{145}{24}$

$\Rightarrow \frac{5}{8}\mathrm{of}9\frac{2}{3}=6\frac{1}{24}$

Hence, $\frac{\mathbf{5}}{\mathbf{8}}$ of $\mathbf{9}\frac{\mathbf{2}}{\mathbf{3}}$ is $\mathbf{6}\frac{\mathbf{1}}{\mathbf{24}}$.