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Question

Find 5 rational numbers between 3 and 4 using x(n+1)n+1,y(n+1)n+1 [4 MARKS]


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Solution

Concept : 1 Mark
Calculation : 2 Marks
Finding the numbers : 1 Mark

x=3 and y=4

Here we have to find 5 natural numbers,

i.e, n=5

Hence using

x(n+1)n+1,y(n+1)n+1

we get 186 and 246

Then the required 5 numbers are 196,206,216,226,236


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