( 5i) ( 35i ) #160; #160; #160; #160; = 3× 55× (i)^2 #160; #160; #160; #160; #160; #160; = 3i^2 we know that i^2= ...

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Properties of Iota

Find -5i35i...

Question

Find $(- 5 i) (\frac{3}{5} i)$ .

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Solution

$(- 5 i) (\frac{3}{5} i)$

$= \frac{- 3 \times 5}{5} \times (i)^{2}$
$= - 3 i^{2}$

we know that $i^{2} = - 1$
$= - 3 (- 1)$ $= 3$

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