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Question

Find 7th term of (4x5−52x)9

A
10050x3
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B
10500x3
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C
1050x3
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D
1000x3
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Solution

The correct option is C 10500x3
7th term of (4x552x)9
T6+1=9C6(4x5)96(52x)6
=9!3!6!(4x5)3(52x)6=10500x3

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