Question

Find $7ab-4bc+3ca$, if $a=2,b=-3$ and $c=5$.

Answer 1

Given the algebraic expression,$7ab-4bc+3ca$

For values $a=2,b=-3$ and $c=5$, putting all the values, we get:

$$\begin{gathered} 7ab-4bc+3ca \\ =7\times 2\times \left(-3\right)-4\times \left(-3\right)\times 5+3\times 5\times 2 \\ =14\times \left(-3\right)-20\times \left(-3\right)+30 \\ =-42+60+30 \\ =-42+90 \\ =48 \end{gathered}$$

Hence,the value of $7ab-4bc+3ca$ for $a=2,b=-3$ and $c=5$ is equal to $48$.