Find:
80+2+110
110=0.1 (count the number of zeros in the denominator and from the extreme right end of the numerator start counting that many numbers and place the decimal point)
So, 80+2+110=80+2+0.1
=82+0.1
=82.1.
Therefore, 80+2+110=82.1
{1(sec2θ−cos2θ)+1(cosec2θ−sin2θ)}(sin2θcos2θ)=1−sin2θcos2θ2+sin2θcos2θ
Write the number given in the following place value table in decimal form:
Hundreds
Tens
Ones
Tenths
Hundredths
Thousandths
100
10
1
110
1100
11000
2
9
0
Solve.
310-14