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Question

Find: (a32a2+5)×(4a1)=

A
4a49a3+2a22a5
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B
4a4+9a3+2a2+20a5
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C
4a49a3+2a2+20a5
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D
4a49a3+20a2+2a5
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Solution

The correct option is B 4a49a3+2a2+20a5
We multiply the given polynomial a32a2+5 and monomial 4a1 as follows:

(4a1)×(a32a2+5)=4a(a32a2+5)1(a32a2+5)=4a48a3+20aa3+2a25=4a49a3+2a2+20a5

Hence, (a32a2+5)×(4a1)=4a49a3+2a2+20a5

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