Find a3+1a3 if a+1a=5
a+1a=5⇒(a+1a)3=(5)3⇒a3+1a3+3a×1a(a+1a)=125⇒a3+1a3+3(5)=125 [a+1a=5]⇒a3+1a3+15=125⇒a3+1a3=125−15⇒a3+1a3=110.
Find a3−1a3 if a−1a=4