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Question

Find a30 given that the first few terms of a geometric sequence are given by 2,1,12,14....

A
1227
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B
1226
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C
1228
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D
1229
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Solution

The correct option is C 1228
In a geometric series an=arn1, where a1 is the first term of the sequence, r is the common ratio, and n is the number of the term to find.

Since the first term is 2 and second term is 1, therefore, the common ratio is :
r=a2a1=12=12

Now we find a30 given that a=2, r=12 and n=30
a30=2(12)29=2(1229)=2229=1228

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