Find A(-5, 7), B(-4, -5), C(-1, -6) and D(4, 5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD.

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Solution

$A (- 5, 7), B (- 4, - 5), C (- 1, - 6), D (4, 5)$
Area $= \frac{1}{2} [\begin{matrix} - 5 & - 4 & - 1 & 4 & - 5 7 & - 5 & - 6 & 5 & 7 \end{matrix}]$
$= \frac{1}{2} (25 + 28 + 24 - 5 - 5 + 24 + 28 + 25) ⟹ \frac{144}{2} = 72$

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