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Nth Term of GP

Find a6 of ...

Question

Find $a_{6}$ of the geometric sequence for which $a_{1} = 4$ , $a_{2} = 36.$

136196

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236196

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336196

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436196

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Solution

The correct option is B $236196$
Given, $a = 4$ , common ratio $= 9$
We know the formula for $n^{t h}$ term,
$a_{n} = a r^{n - 1}$
Therefore, $a_{6} = 4 \times 9^{6 - 1}$
$= 4 \times 9^{6 - 1}$
$= 4 \times 9^{5}$
$= 236196$

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Similar questions

a_{1}, a_{2}, a_{3} . . . . .

a_{1}, a_{2}, a_{4}, a_{6} . . . . .

A P s

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a_{2}, a_{3}, a_{4}

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a_{1} = 10

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a_{1} = 0

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a_{3} = 4

a_{5} = 20

a_{6}

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