Question

Find 'a' and 'b'

${15}^2+a^2=b^2$

• A. 8,9
• B. 8,16
• C. 8,17
• D. 9,16

Answer 1

The correct option is C

8,17

$m^2-1,2m,m^2+1$ forms a Pythagorean triplet

As the given number (15) is odd, it can't be of the form 2m.

$\therefore m^2-1=15$

$m^2=16$

(16 is a perfect square.)

$\Rightarrow m=4$

$2m=2\times 4=8$

$m^2+1=4^2+1=16+1=17$

So, a = 8
and b = 17