Find A and B. [3 MARKS] 2 A B+ A B 1 B 1 8
Concept: 1 Mark Application: 2 Marks B + 1 = 8. B = 7. The last digit of B + A = 1. Hence A = 4 such that 7+ 4 = 11. Hence A = 4, B = 7.
Find the value of the polynomial a3+3a2b+2ab−b2 at a=−2 and b=3. [2 MARKS]
Prove the following identities : (i) (a+b)2=a2+b2+2ab (ii) (a−b)2=a2+b2−2ab [2 MARKS]