Find a and b if (a+ib)(1+i)=2+i.
Step 1: Simplify the given expression
Given, (a+ib)(1+i)=2+i
⇒a+ai+ib+i2b=2+i⇒a+ai+ib-b=2+i⇒a-b+a+bi=2+i
Step 2: Compare RHS and LHS and solve
⇒a-b=2…i⇒a+b=1…ii
Now, solving the two equations we get,
⇒2a=3⇒a=32
and,
⇒b=1-32⇒b=-12
Hence, the required answer is a=32,b=-12.