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Question

Find a,b,c,d if [d+110+a3b2a4]=[22a+1b54c]

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Solution

Equating the corresponding elements of the two matrices, we have
d+1=2d=21=1
10+a=2a+1
2aa=101
a=9
3b2=b53bb=5+2
2b=3
2b=3
b=32
a4=4c
4c=a4=94=5
c=54
a=9,b=32,c=54,d=1


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