Find a,b,c,d so that the line x=ay+b,z=cy+d must pass through the points (3,1,−3)(4,2,−4) and also show that the given points and (5,3,−5) are collinear.
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Solution
Let A(3,1,−3), B(4,2,−4) and C(5,3,−5) are points
Line 1:
x=ay+b ………..(1)
Put A&B lie on line
3=a+b
and 4=2a+b
⇒a=1,b=2
Line 2:
z=cy+d
Put A&B lie on line
−3=c+d
and −4=2c+d
c=−1, d=−2
Put C in (1)
5=3×1+2=5
Hence C lies on line 1 which A & B lie, hence A, B are collinear.