Find-a-b-c -a-b-c-A- a2-2 a b-c2B- a2-4 a b-b2-c2C- a2-2 a b-b2D- a2-2 a b-b2-c2

The correct option is D a^2 nbsp;+ 2ab + b^2 nbsp; c^2 (a+b+c)×(a+b c) =(a^2 nbsp;+ ab nbsp;ac + ab + b^2 nbsp; bc + nbsp;ac + bc c^2) = (a^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Algebraic Identity: (a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ac

Find:a+b+c ×a...

Question

Find:
$(a + b + c) \times (a + b - c) =$

$a^{2} + 2 a b - c^{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$a^{2} + 4 a b + b^{2} - c^{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$a^{2} + 2 a b + b^{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$a^{2} + 2 a b + b^{2} - c^{2}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
$a^{2} + 2 a b + b^{2} - c^{2}$

$(a + b + c) \times (a + b - c)$
$= (a^{2} + a b - a c + a b + b^{2} - b c + a c + b c - c^{2})$
$= (a^{2} + 2 a b + b^{2} - c^{2})$

Suggest Corrections

Similar questions

If a + b + c = 2s, then prove the following identities

(a) s² + (s − a)² + (s − b)² + (s − c)² = a² + b² + c²

(b) a² + b² − c² + 2ab = 4s (s − c)

(d) a² − b² − c² + 2ab = 4(s − b) (s − c)

(e) (2bc + a² − b² − c²) (2bc − a² + b² + c²) = 16s (s − a) (s − b) (s − c)

(f)

If (a-b) sin ( $θ + ϕ$ ) = (a+b) sin ( $θ + ϕ$ ) and a tan $(\frac{θ}{2})$ - btan $(\frac{ϕ}{2})$ = C,the the value of sin $ϕ$ is equal

Q. Question 3

Which of the following is correct?
a)

(a - b)^{2} = a^{2} + 2 a b - b^{2}

(a - b)^{2} = a^{2} - 2 a b + b^{2}

(a - b)^{2} = a^{2} - b^{2}

(a + b)^{2} = a^{2} + 2 a b - b^{2}

Which of the following is correct?
a) $(a - b)^{2} = a^{2} + 2 a b - b^{2}$
b) $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

Q. If a cos θ − b sin θ = c, then a sin θ + b cos θ =

(a)

\pm \sqrt{a^{2} + b^{2} + c^{2}}

(b)

\pm \sqrt{a^{2} + b^{2} - c^{2}}

(c)

\pm \sqrt{c^{2} - a^{2} - b^{2}}

(d) None of these

Join BYJU'S Learning Program

Find: (a+b+c)×(a+b−c)=

The correct option is D a2+2ab+b2−c2 (a+b+c)×(a+b−c) =(a2+ab−ac+ab+b2−bc+ac+bc−c2) =(a2+2ab+b2−c2)

Find:
$(a + b + c) \times (a + b - c) =$

The correct option is D
$a^{2} + 2 a b + b^{2} - c^{2}$

$(a + b + c) \times (a + b - c)$
$= (a^{2} + a b - a c + a b + b^{2} - b c + a c + b c - c^{2})$
$= (a^{2} + 2 a b + b^{2} - c^{2})$