500
Question
Find a cubic polynomial with its zeros as 3,−1 and −3 respectively.
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Solution
Roots are 3,−1,−3Sum of roots =3+(−1)+(−3)=−1Sum taken two at a times=(3)(−1)+(−1)(−3)+(3)(−3) =−9Product=(3)(−1)(−3) =9f(x)=K(x3+x2−9x−9)
Sum of roots =3+(−1)+(−3)=−1
Sum taken two at a times=(3)(−1)+(−1)(−3)+(3)(−3)
=−9
Product=(3)(−1)(−3)
=9
f(x)=K(x3+x2−9x−9)
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