Find $A \cup B$ and $A \cap B$ when:
$A$ is the set of all positive real numbers and $B$ is the set of all negative real numbers

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Solution

$A = {1, 2, 3, 4, 5, 6.......}$
$B = {- 1, - 2, - 3, - 4, - 5.......}$
$A \cup B = {. . . . . . . . . . . . . ., - 6, - 5, - 4, - 3, - 2, - 1, 1, 2, 3, 4, 5, 6......}$
$A \cap B = ϕ$

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