Find a, if the coefficients of x2 and x3 in the expansion of (3+ax)9 are equal.
We have,
(3+ax)9=9C0×39+9C1×38×(ax)1+9C2×37×(ax)2+9C3×36×(ax)3+...
∵ Coefficient of x2=9C2×37×a2 and, Coefficient of x3=9C3×36×a3
Now, Coefficient of x2 =Coefficient of x3
⇒9C2×37×a2=9C3×36×a3
⇒36×37×a2=84×36×a3
⇒a=36×3784×36=97