Find $a$ if $x^{4} - 20 x^{3} - 93 x^{2} - 20 x + 3 a = 0$ for $x = 1$ .

42

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43

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44

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45

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Solution

The correct option is C $44$
Put $x = 1$ in given $e q^{n}$
$\Rightarrow 1 - 20 - 93 - 20 + 3 a = 0$
$\Rightarrow 3 a = 132$
$\Rightarrow a = 44$

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