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Question

Find a L.C.M. [Least Common Multiple] of the following:
x3+y3,x3y3,x4+x2y2+y4

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Solution

Given, x3+y3,x3y3,x4+x2y2+y4
x3+y3=(x+y)(x2xy+x2)
x3y3=(xy)(x2+xy+y2)
x4+x2y2+y4=(x2+y2)2x2y2
=(x2+y2)2(xy)2
=(x2+y2+xy)(x2+y2xy)
L.C.M. =(x+y)(x2xy+y2)
(xy)(x2+xy+y2)
=(x3+y3)(x3y3)
=(x3)2y3)2x6y6

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