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Method of Finding LCM

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Question

Find a number greater than 3 which when divided by 4, 5, and 6 always leaves the same remainder 3

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Solution

The smallest number which when divided by 4, 5 and 6 leaves the remainder 3 in each case is $L C M (4, 5 a n d 6) + 3$
$= 60 + 3 = 63$

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