Question

Find a particular solution of the differential equation, given that y = – 1, when x = 0 (Hint: put x – y = t)

Answer 1

Substituting the values of x – y and in equation (1), we get:

Integrating both sides, we get:

Now, y = –1 at x = 0.

Therefore, equation (3) becomes:

log 1 = 0 – 1 + C

⇒ C = 1

Substituting C = 1 in equation (3) we get:

This is the required particular solution of the given differential equation.