wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find a point on the x-axis, which is equidistant from the points (5, 4) and (2, 3).


A

(152,0)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

(143,0)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

(277,0)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

(103,0)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

(143,0)


Let point (x,0) is the point on the x-axis that is equidistant from the points (5, 4) and (2, 3).

Accordingly,

(5x)2+(40)2=(2x)2+(30)2

Squaring on both sides, we get,

52+x210x+16=4+x24x+9

4110x=134x

6x=28

x=143

Thus, required point on the x-axis is (143,0)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Distance Formula
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon