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Question

Find a point on x-axis which is equidistant from (2, -5) and (-2, 9)

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Solution

Let the required point on the x-axis be (x,0).

Therefore,
(x2)2+(5)2=(x+2)2+(9)2

(x2)2+25=(x+2)2+81

x2+44x+25=x2+4+4x+81

8x=2581=56

x=7

hence, the required point is (7,0).

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