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Question

Find a polynominal f(x) of degree 2 where f(0)=8,f(1)=12,f(2)=18.

A
x2+3x8
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B
x23x+8
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C
2x2x+3
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D
x2+3x+8
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Solution

The correct option is D x2+3x+8
Let the polynomial is ax2+bx+c.
Now, f(0)=8
c=8
Equation is ax2+bx+8.
Again, f(1)=12a+b+8=12
a+b=4 .....(i)
and f(2)=18
4a+2b+8=18
2a+b=5 ......(ii)
On solving Eqs. (i) and (ii), we get
a=1,b=3
Required equation is x2+3x+8.

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