Find a polynominal f(x) of degree 2 where f(0)=8,f(1)=12,f(2)=18.
A
x2+3x−8
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B
x2−3x+8
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C
2x2−x+3
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D
x2+3x+8
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Solution
The correct option is Dx2+3x+8 Let the polynomial is ax2+bx+c. Now, f(0)=8 ⇒c=8 ∴ Equation is ax2+bx+8. Again, f(1)=12⇒a+b+8=12 ⇒a+b=4.....(i) and f(2)=18 ⇒4a+2b+8=18 ⇒2a+b=5 ......(ii) On solving Eqs. (i) and (ii), we get a=1,b=3 ∴ Required equation is x2+3x+8.