Question

Find a positive number which when increased by $17$ is equal to $60$ times the reciprocal of the number.

• A. $3$
• B. $10$
• C. $17$
• D. $20$

Answer 1

Answer: (A)

$3$

Let the positive number be $x$.

Then by the problem,

$x+17=\frac{60}{x}$

or, $x^2+17x-60=0$

or, $(x-3)(x+20)=0$

Since the number is positive, so $x=3$.

The required number is $3$.