Question

Find a pythagorean triplet whose one number is $15$.

Answer 1

Find Pythagorean triplets

Pythagorean Triplets are in the form of $m^2-1,2m$ and $m^2+1$.

So, the first number is $15$.

$$\begin{gathered} \Rightarrow m^2-1=15 \\ \Rightarrow m^2=16 \\ \Rightarrow m=4 \end{gathered}$$

Second Number is

$\Rightarrow 2m=2\times 4=8$.

And third number is

$$\begin{gathered} \Rightarrow m^2+1 \\ ={\left(4\right)}^2+1 \\ =17 \end{gathered}$$

Hence, the Pythagorean triplets are $8,15$ and $17$.