Find a quadratic polynomial with $4$ and $5$ as the zeros of polynomial

x^{2} - 9 x + 20

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x^{2} - 5 x + 9

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x^{2} - 4 x + 5

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None of these

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Solution

The correct option is A $x^{2} - 9 x + 20$
The quadratic polynomial with $4$ and $5$ as zeros of polynomial is given as

$\Rightarrow$ $(x - 4) (x - 5)$

$\Rightarrow$ $x^{2} - 4 x - 5 x + 20$

$\Rightarrow$ $x^{2} - 9 x + 20$

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Similar questions

A quadratic polynomial whose zeros are $5$ and $- 3,$ is

(a) $x^{2} + 2 x - 15$

(b) $x^{2} - 2 x + 15$

(d) none of these

x^{2} - 5 x + 6

(x + 5), (x^{2} + 4 x + 16)

x^{2} + 9 x + 20

y = x^{2} - 4 x + 4

x^{2} - 4 x + 3

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