Question

Question 166

Find a repeater machine that will do the same work as a $(\times \frac{1}{8})$ machine.

Answer 1

Since, $\frac{1}{8}are\frac{1}{2},\frac{1}{2},\frac{1}{2},$
So, $\frac{1}{8}=\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}={\left(\frac{1}{2}\right)}^3$
Hence, $(\times \frac{1}{2^3})$ repeater machine can do the same work as a $(\times \frac{1}{2})$ machine.