Find a smallest four digit number using the digits $7, 8, 9, 5$ such that the number thus formed has $9$ at its hundreds place and $8$ at its one's place.

5978

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7598

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7958

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7985

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Solution

The correct option is B $5978$
The ascending order of the given numbers $7, 8, 9, 5$ is:

$5 < 7 < 8 < 9$

We observe that the smallest digit is $5$ and the largest digit is $9$ .
Therefore, the smallest number formed is $5789$ .

But it is given that the number formed should have $9$ at its hundredth place and $8$ at its one's place, therfore, the required number is:

$5978$ where $8$ is at one's place, $7$ is at tens place, $9$ is at hundredth place and $5$ is at thousandth place.

Hence, the smallest $4$ digit number formed is $5978$ .

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Find a smallest four digit number using the digits 7,8,9,5 such that the number thus formed has 9 at its hundreds place and 8 at its one's place.

Find a smallest four digit number using the digits $7, 8, 9, 5$ such that the number thus formed has $9$ at its hundreds place and $8$ at its one's place.