Question

Find a solution of the linear equation $2\sqrt{2}x-3y+4=0$ corresponding to $y=2$.

Answer 1

According to question,

put $y=2$

$\begin{array}{c}\Rightarrow 2\sqrt{2}x-2=0\\ \Rightarrow x=\frac{1}{\sqrt{2}}\\ weget,\\ \left(\frac{1}{\sqrt{2}},2\right)\end{array}$