Question

Find (a) the total number and (b) the total mass of protons in 34 mg of $N{H}_3$ at STP.

Answer 1

$34$ $mg$ of $N{H}_3$

$a.$ No. of protons$=7+3=10$

$b.$ Mass of protone$=1.6726\times {10}^{-27}$ $kg$.

$a)$ It would contain $6.022\times {10}^{24}$ protons.

$0.034g$ would contain $\frac{6.022\times {10}^{24}}{17}\times 0034=1.2044\times {10}^{22}$ protons.

$b)$ mass$=(1.6726\times {10}^{-27}kg)(1.2044\times {10}^{22})=2.0145\times {10}^{-5}kg$