1
Question
Find a unit vector in direction of →A=5^i+^j−2k
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Solution
→A=5^i+^j−2^k
MAgnitude of vector =√25+1+4
^A=1√30(5^i+^j−2^k)
MAgnitude of vector =√25+1+4
^A=1√30(5^i+^j−2^k)
^A=1√30(5^i+^j−2^k)
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0
which
has magnitude 8 units.