Given:→a=→i+→j+→k and →b=→i+2→j+ 3→k
(→a+→b)= (^i+^j+^k)+(^i+2^j+3^k)
(→a+→b)=2^i+3^j+4^k
(→a−→b)=(^i+^j+^k)−(^i+2^j+3^k)
→a−→b=0^i−^j−2^k
Let →c=(→a+→b)×(→a−→b)
⇒→c=∣∣
∣
∣∣^i^j^k2340−1−2∣∣
∣
∣∣
→c=^i[(3×−2)−(−1×4)]−^J[(2×−2)−(0×4)]+^k[(2×−1)−(0×3)]
→c=^i[−6−(−4)]−^j[−4−0]+^k[−2−0]
→c=−2^i+4^J −2^k
Unit vector →c=→cmagnitude of →c
^c=(−2^i+4^j−2^k)√(−2)2+(4)2+(−2)2
^c=(−2^i+4^j−2^k)√4+16+4
^c=(c−2^i+4^j−2^k)2√6
Unit vector→c(^c)=−1√6^i+2√6^j−1√6^k
Hence, the unit vector→cis →c=−1√6^i+2√6^j−1√6^k