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Question
Find a vector in the direction of the vector 3^i−^j+4^k, which has magnitude 6 units.
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Solution
We have,→a=3^i−^j+4^k^a=3^i−^j+4^k√26
Since,→b=6^a
Therefore,=6(3^i−^j+4^k)√26
Hence, this is the answer.
→a=3^i−^j+4^k^a=3^i−^j+4^k√26
Since,
→b=6^a
Therefore,
=6(3^i−^j+4^k)√26
Hence, this is the answer.
Suggest Corrections
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which
has magnitude 8 units.