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Question

Find a vector r in the plane of p=^i+^j and q=^j+^k such that r is perpendicular to p and r.q=2

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Solution

We have,
¯¯¯r=x¯¯¯p+y¯¯¯q
=x(¯i+¯j)+y(¯j+¯¯¯k)
¯¯¯r=x¯i+(xy)¯j+y¯¯¯k¯¯¯r.¯¯¯p=0¯¯¯r.¯¯¯p=2[x¯i+(xy)¯j+y¯¯¯k].(¯i+¯j)=0x+xy=02x=y¯¯¯r.¯¯¯q=2yx+y=22yx=24xx=2x=23y=43¯¯¯r=23¯¯¯p43¯¯¯q

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