Question

Find acceleration of 3kg block? Given string and pulleys are massless. Pulley and wedge is frictionless and wedge is fixed.

• A. 2m/
• B. 4m/
• C. 10m/
• D. 3 m/

Answer 1

The correct option is A

2m/

Since string is inextensible so the acceleration of all parts of string will be same.

So if $m_1$ = 2kg block slides down with acceleration 'a' then $m_2$ = 3kg block moves left with acceleration a

FBD

2g sin $\theta$ - T = 2a ----------------(i)

T = 3a ---------------------(ii)

Adding (i) & (ii)

$2\times 10\times \frac{1}{2}=5a$

a = 2m/$s^2$