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Byju's Answer
Standard XII
Mathematics
Adjoint of a Matrix
Find adjoint ...
Question
Find adjoint of matrix :
∣
∣ ∣
∣
1
−
1
2
2
3
5
−
2
0
1
∣
∣ ∣
∣
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Solution
M
11
=
3
M
12
M
13
=
6
M
21
=
−
1
M
22
=
5
M
23
−
2
M
31
=
−
11
M
32
=
1
M
33
=
5
C
11
=
3
C
12
=
−
12
C
13
=
6
C
21
=
1
C
22
=
5
C
23
=
2
C
31
=
−
11
C
32
=
−
1
C
33
=
5
co factor matrix
⎡
⎢
⎣
3
−
12
6
1
5
2
−
11
−
1
5
⎤
⎥
⎦
Adj A = Transpose of co-factor matrix
⎡
⎢
⎣
3
−
12
6
1
5
2
−
11
−
1
5
⎤
⎥
⎦
Adj A
=
⎡
⎢
⎣
3
1
−
11
−
12
5
−
1
6
2
5
⎤
⎥
⎦
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