Find all complex numbers $z$ which satisfy the following equation
$¯ z = 2 - z$

z = 1 + i y .

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z = - 1 + i y .

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z = x + i .

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z = x - i .

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Solution

The correct option is A $z = 1 + i y .$
Put $z = x + i y$ in $¯ z = 2 - z$

We get $x - i y = 2 - x - i y$

$\Rightarrow x = 1$

Therefore, $z = x + i y = 1 + i y$
Ans: A

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