Find all pairs of consecutive odd numbers natural, such that both of which are larger than 10, and their sum is less than 40.
A
(11,13),(13,15),(15,17),(19,21)
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B
(9,11),(13,15),(15,17),(17,19)
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C
(11,13),(13,15),(15,17),(17,19)
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D
(11,13),(13,15),(15,17),(21,23)
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Solution
The correct option is C(11,13),(13,15),(15,17),(17,19) Only C satisfies the conditions mentioned in the question. In A and D set (19,21) has sum equal to 40. But the sum should be less than 40. In B set (9,11) has 9 which is less than 10.