The given function is f(x)=⎧⎨⎩x|x|ifx<0−1ifx≥0
It is known that x<0⇒|x|=−x
Therefore, the given function can be rewritten as
f(x)=⎧⎨⎩x|x|=x−x=−1ifx<0−1ifx≥0
⇒f(x)=−1 for all x∈R
Let
c be any real number. Then, limx→cf(x)=limx→c(−1)=−1
Also, f(c)=−1=limx→cf(x)
Therefore, the given function is a continuous function.
Hence, the given function has no point of discontinuity.