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Question

Find all positive integers m,n such that (3m)n=3m×3n

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Solution

Suppose, (3m)n=3m×3n
(3)mn=(3)m+n
mn=m+n
mnmn=0
mnmn+11=0
m(n1)(n1)=1
(m1)(n1)=1
m1=1 and n1=1
m=2 and n=2

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